Answer:
red balls = x
blue balls = 12
white balls = 2x + 4
total balls in a box = x + 12 + (2x + 4) = 3x + 16
a.) what is the value of x?
Solution:
Probability of picking red = 1/5
[tex] \frac{1}{5} = \frac{x}{3x + 16} [/tex]
[tex]3x + 16 = 5x[/tex]
[tex]2x = 16[/tex]
[tex]x = 8[/tex]
there are 8 red balls inside the box.
b.) With replacement, what is the probability of selecting a blue ball.
Solution:
[tex]P = ( \frac{8}{3x + 16} )( \frac{12}{3x + 16} )[/tex]
since the value of x = 8, the total number of balls in the box = 3(8) + 16 = 40
[tex]P = ( \frac{8}{40} )( \frac{12}{40}) [/tex]
[tex]P = \frac{3}{50} [/tex]
