Sagot :
The answer is 299.
f(n)=2+3(n−1)=3n−1
Examples
f(1)=3×1−1=2
f(2)=3×2−1=5
f(3)=3×3−1=8
f(4)=3×4−1=11
f(5)=3×5−1=14
f(100)=3×100−1=299
The answer is 299.
f(n)=2+3(n−1)=3n−1
Examples
f(1)=3×1−1=2
f(2)=3×2−1=5
f(3)=3×3−1=8
f(4)=3×4−1=11
f(5)=3×5−1=14
f(100)=3×100−1=299