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1) A billboard is in the shape of a parallelogram. The
billboard has a base of 48 feet and a height of 14 feet.
Find the area of the billboard.
SOLUTION:

2) A trapezoidal window has a height of 18 cm. The bases
of the window are 34 and 28 cm. long. What is the area
of the window?
SOLUTION:

3) A triangular bandage has a base of 18 inches and a
height of 12 inches Calculate its area
SOLUTION;​


1 A Billboard Is In The Shape Of A Parallelogram Thebillboard Has A Base Of 48 Feet And A Height Of 14 FeetFind The Area Of The BillboardSOLUTION2 A Trapezoidal class=

Sagot :

1.

Area of a Parallelogram

A = bh

where

A = Area = ?

b = base = 48 ft

h = height = 14 ft

A = bh

A = (48)(14)

A = 672 ft²

2.

Area of trapezoid

[tex]\large{area \: = \frac{(b1 \: + \: b2)}{2} h}[/tex]

where,

b1 = base1 = 28 cm

b2 = base2 = 34 cm

h = height = 18 cm

solve for area,

[tex]area \: = \frac{(b1 \: + \: b2)}{2} h \\ \\ area \: = \frac{(28 \: + \: 34)}{2} (18) \\ \\ area \: = 558 \: cm^{2} [/tex]

3.

Area of Triangle

A∆ = ½bh

where

A = Area = ?

b = base = 18 in

h = height = 12 in

A∆ = ½bh

A∆ = ½(18)(12)

A∆ = 108 in²