👤
Breihazeleego
Answered

A. Boyle's law

formula: P1V2=P2V2

1. a gas occupies 12.3 liters at a pressure of 20.0 mmHg what is the valume when the pressure increased to 50.0 mmHg?

2. If a gas at 25.0 °C occupies 3.60 liters at a pressure of 2.00 atm, what will be it's volume at a pressure of 3.50 atm?

B. Charlie's law

formula:
V1 V2
— = —
T1 T2

1. 600.0 mL of air is at 15.0 °C. what is the volume at 50.0 °C?

2. A gas occupies 900.0 mL at a temperature of 32.0 °C. what is the volume at 112.0 °C?​

Sagot :

Kishaaxelgo

Answer:

A

1. 4.92L

given:

P1 = 12.3 liters

P2 = 20.0 mmHg

V1 =50.0 mmHg

V2 = ?

Equation: V2=P1V1/P2

=12.3 L(20.0mmHg)/50.0mmHg

=246L/50.0

= 4.92L

Repeat the process on number 2 since V2 rin ang hinahanap.

B.

(ilalagay ko nalang yung gagamitin na equation

1. V2=V1×T2/T1

2. V2=V1×T2/T1

Go Training: Other Questions