Sagot :
if the diameter of a circle is 23dm what is the area
FORMULA
- [tex]{ \large{ \rightarrow{ \tt{A = \frac{π {d}^{2} }{4} }}}} \\ [/tex]
SOLVE
[tex]{ \tt{A = \frac{π {d}^{2} }{4} }}\\ { \tt{A = \frac{(3.14) {(23dm)}^{2} }{4} }}\\ { \tt{A = \frac{(3.14)(529)}{4} }}\\ { \tt{A = \frac{1661.06}{4} }}\\ { \large{ \boxed{ \pink{ \tt{A =415.265dm}}}}}\\ [/tex]
ANSWER
- The area of a circle with it's given diameter is 415.265dm
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[tex]\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]
⟩ If the diameter of a circle is 23dm what is the area?
GIVEN:
- Diameter - 23dm
FORMULA:
- [tex]\large\sf\purple{}A = \frac{\pi \: d {}^{2} }{4} [/tex]
SOLUTION:
- [tex]\large\sf\purple{}A = \frac{\pi \: d {}^{2} }{4} [/tex]
- [tex]\large\sf\purple{}A = \frac{(3.14)(23) {}^{2} }{4} [/tex]
- [tex]\large\sf\purple{}A = \frac{(3.14)(529)}{4} [/tex]
- [tex]\large\sf\purple{}A = \frac{1,661.06}{4} [/tex]
- [tex]\large\sf\purple{A = 415.265dm {}^{2} }[/tex]
ANSWER:
- The area of the circle is 415.265dm².
[tex]\huge\purple{\overline{\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]
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