Sagot :
Given:
moles of solute = 2 mol
mass of solvent = 3 kg = 3000 g
[tex]P_{\text{solvent}} = \text{75 torr}[/tex]
solute: glucose
solvent: benzene
Required:
[tex]P_{\text{solution}}[/tex]
Solution:
First Step: Calculate the molar mass of solvent.
molar mass of solvent = (12.01 g/mol × 6) + (1.008 g/mol × 6)
molar mass of solvent = 78.108 g/mol
Second Step: Calculate the number of moles of solvent.
[tex]\text{moles of solvent} = \dfrac{\text{mass of solvent}}{\text{molar mass of solvent}}[/tex]
[tex]\text{moles of solvent} = \dfrac{\text{3000 g}}{\text{78.108 g/mol}}[/tex]
moles of solvent = 38.40836 mol
Third Step: Calculate the mole fraction of solvent.
[tex]X_{\text{solvent}} = \dfrac{\text{moles of solvent}}{\text{moles of solute + moles of solvent}}[/tex]
[tex]X_{\text{solvent}} = \dfrac{\text{38.40836 mol}}{\text{2 mol + 38.40836 mol}}[/tex]
[tex]X_{\text{solvent}} = 0.9505053[/tex]
Last Step: Calculate the vapor pressure of the solution.
[tex]P_{\text{solution}} = X_{\text{solvent}}P_{\text{solvent}}[/tex]
[tex]P_{\text{solution}} = (0.9505053)(\text{75 torr})[/tex]
[tex]\boxed{P_{\text{solution}} = \text{71 torr}}[/tex]
Answer:
[tex]P_{\text{solution}} = \text{71 torr}[/tex]
[tex]\\[/tex]
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