For no. 1
Cavan, C = 0.2 cu. m
Volume, V = 3m x 2m x 2m = 12 cu. m
No. of cavans, N = V/C
N = 12/0.2
N = 60
Therefore, 60 cavans of rice
For no. 2
I don't think a 7mm height of a cone is possible for a 6m wide circular disk. It would be just be assumed like a sundial or a flat circular disk. However if 7mm is supposed to be 7m then:
Volume, V = ⅓πr²h
V = ⅓π(3)²(7)
V = 65.97 cu. m