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1. c= 20 and a = 12, find b,<B, and <A

Sagot :

Answer:

b = 16

∠A = 36.87°

∠B = 53.13°

Step-by-step explanation:

I assume that the given triangle is a Right Triangle

Therefore, I used Pythagorean Theorem

b = √(c^2 - a^2)

b = √(20^2 - 12^2)

b = √(256)

b = 16

∠A = arcsin (a /c)

= arcsin ( 12/20)

= arcsin(0.6)

= 36.87°

∠B = arcsin (b/c)

= arcsin (16/20)

=arcsin (0.8)

= 53.13°