Answer:
The molality of the solution is 8.919 molal.
Explanation:
Molality (m) is defined as moles of solute per kilogram of solvent. On the other hand, molarity (M) is a unit of concentration which has a unit of moles of solute per liters of solution.
Let us keep these in mind as we go further to the solution for this problem.
Given:
5.86 M (molar) of ethanol (C₂H₅OH)
Required:
Molality (m)
Solution:
We assume 1 liters of solution for this problem.
Get first the molar mass (MM) of the ethanol.
MM ethanol = (12.012 g/mol*2) + (1.008*5) + (15.999) + (1.008)
MM ethanol = 46.071 g/mol
Getting the mass of ethanol from 5.86 M, we have,
5.86 moles ethanol (since we assume 1 L of solution)
5.86 moles ethanol * 46.071 g/mol = 269.9761 grams ethanol
Getting the mass of solution from the density, we have,
0.927 g/mL * 1000 mL = 927 grams solution
(We used multiplier 1000 mL because 1 L = 1000 mL)
Solving for the mass of solvent, we have,
mass of solvent = mass of solution - mass of solute
mass of solvent = 927 grams - 269.9761 grams
mass of solvent = 657.024 grams solvent = 0.657024 kilograms solvent
Solving for molality, we have,
m = moles solute ÷ kilograms of solvent
m = 5.86 moles of ethanol ÷ 0.657024 kg solvent
m = 8.919
Therefore, the molality of the solution is 8.919 molal.
Answer:
7.34 m
Explanation:
Answer can be found in this link: https://www.assignmentexpert.com/homework-answers/chemistry/organic-chemistry/question-137007
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