patulong po nito please
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[tex]\huge\color{IRON}\{\boxed{\tt{ANSWER:}}[/tex]
[tex]1. \: \frac{1}{2} [/tex]
[tex]2. \: \frac{9}{16} [/tex]
[tex]3. \: \frac{2}{7} [/tex]
[tex]4. \: \frac{2 + 14}{11} = \frac{4}{11} [/tex]
[tex] \: [/tex]
[tex]\huge\color{IRON}\{\boxed{\tt{SOLUTION:}}[/tex]
[tex] \: [/tex]
[tex]1. \: There \: are \: 6 \: numbers \: on \: a \: dice \\ [/tex]
[tex]odd \: numbers = 1 \: 3 \: and \: 5[/tex]
[tex]p = \frac{3}{6} = \frac{1}{2} [/tex]
[tex] \: [/tex]
[tex]2. \: p = \frac{18}{12 + 18 + 2} = \frac{18}{32} = \frac{9}{16} [/tex]
[tex] \: [/tex]
[tex]3. \: p = \frac{6}{6 + 5 + 10} = \frac{6}{21} = \frac{2}{7} [/tex]
[tex] \: [/tex]
[tex]4. \: There \: are \: two \: A's \: one \: E \: and \: one \: I [/tex]
[tex]p = \frac{2 + 14}{11} = \frac{4}{11} [/tex]