30. In a particular location, from school to James house and to the church formed 120°. The distance from
school to church is 10km while James house to the church is 5 km. In finding the distance between the school
and James house, which of the following is a helpful equation?
school
a=10
church
1200
Jame's house
sinx
sin 120°
sin y
sin 120°
A.
10
C.
---
10
5
5
siny
sinx
sin 120°
В.
5
sin 120°
D.
5
10
10​