👤
Marjorienicolas183go
Answered

The system gains 2500 J of heat in addition to the work done on the system by the surrounding which is 2000 J. Calculate the change in the internal energy of the system.

Sagot :

FierceFireflieego

Answer:-

  • Internal energy before work done=E_1=2000J
  • Internal energy after work done=E_2=2500J
  • Change in internal energy=E_net

we know

[tex]\boxed{\sf E_{net}=E_2-E_1}[/tex]

[tex]\\ \sf\longmapsto E_{net}=2500-2000[/tex]

[tex]\\ \sf\longmapsto E_{net}=500J[/tex]

Go Training: Other Questions