Answer:
In rolling of 2dice total number of outcomes are 6^2 i.e. n(S)=36
And let E be the event that dots on the second dice is less than the dots on the first i.e.
E={ (6,5),(6,4),(6,3),(6,2),(6,1),(5,4),(5,3),(5,2),(5,1),(4,3),(4,2),(4,1),(3,2),(3,1),(2,1)}
and n(E)= 15
And P(dots on second die is less) = n(E)/n(S) = 15/36 = 5/12.
