[tex]\Large\color{blue}{{\underline{\mathfrak {{꧁☆☬ Answer ☬☆꧂ }}}}}[/tex]
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[tex]\small\color{black}{{\underline{\bold{Using \:the \: law \: of \:sine}}}}[/tex]
[tex]\small\color{black}{{\underline{\bold{\frac{10}{ \sin(A) } = \frac{19}{ \sin(120) } } }}} \\ \\ = \sin {}^{ - 1} (A) = \frac{10 \sin(120) }{19} \\ =\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: A=27.1\:\:\:\: }}}}[/tex]
[tex]\small\color{black}{{\underline{\bold{{27.1°+B+120°=180° } } }}}\\= < B=147.1-180°\\ = \small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: B=32.9\:\:\:\: }}}}[/tex]
[tex]\small\color{black}{{\underline{\bold{\frac{10}{\sin(27.1) } = \frac{b}{ \sin(32.9) }}}}} \\ \\ b = \frac{10 \sin(32.9) }{ \sin(27.1) } \\ =\small\color{red}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\: b=11.9\:\:\:\: }}}}[/tex]
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