Direction: 1. Lines p and q are cut by transversal r. Find the value of x that makes p ll q
Answer:
a.<2 and <7 are alternate interior angles, m<2 = 5x – 11 and m<7 = 3x + 7.
x=9
b.<1 and <4 are some-side exterior angles, m<1 = 6x + 3 and m<4 = 4x + 7.
x=2
Solution:
#TO FIND THE VALUE OF "X"
a. Given: (m<2 = 5x – 11 and m<7 = 3x + 7)
m<2=m<7
5x-11=3x+7
5x-3x=7+11
2x=18
2x/2=18/2 (Divide both sides by 2)
x=9
#Check first
#Substitute x by 9
#If x=9
m<2=m<7
5x-11=3x+7
5(9)-11=3(9)+7
(45)-11=(27)+7
34=34
b. Given: (m<1 = 6x + 3 and m<4 = 4x + 7)
m<1=m<4
6x+3=4x+7
6x-4x=7-3
2x=4
2x/2=4/2 (Divide both sides by 2)
x=2
#Check first,
#Substitute x by 2
#If x=2
m<1=m<4
6x+3=4x+7
6(2)+3=4(2)+7
(12)+3=(8)+7
15=15
Explanation: They are both equal and correct to each other when you finding the value of x then replaced x by any number that it depends on the given equation.
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