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A. Find the missing term in each sequence.
1. 31. 10, 15, 20, 25, _______?
2. 32. -2 , -4 , -6 , ____ , -10 
3. 33. 1, 3 , 9 , 27 , ____ ,?
4. 34. 7, 12 , 22 , _____, 57 , 82 , 
5. 35. 1, 4, 9 , 16, _____ , 36, 49 ​


Sagot :

Answer:

30

-8

81

37

25

Step-by-step explanation:

correct me if I'm wrong

Directions: A. Find the missing term in each sequence.

Answer:

31) 10, 15, 20, 25, 30

32) -2, -4, -6, -8, -10

33) 1, 3, 9, 27, 81

34) 7, 12, 22, 37, 57, 82

35) 1, 4, 9, 16, 25 , 36, 49

Solution:

#TO FIND THE NEXT TERM

31) 10, 15, 20, 25, 30

#Added by 5

a1=10

a2=(10+5)=15

a3=(15+5)=20

a4=(20+5)=25

a5=(25+5)=30

32) -2, -4, -6, -8, -10

#Subtracted by -2

a1=-2

a2=(-2-2)=-4

a3=(-4-2)=-6

a4=(-6-2)=-8

a5=(-8-2)=-10

33) 1, 3, 9, 27, 81

#Multiply by 3

a1=1

a2=(1 x 3)=3

a3=(3 x 3)=9

a4=(9 x 3)=27

a5=(27 x 3)=81

34) 7, 12, 22, 37, 57, 82

#Added by multiple of 5 (5,10,15,20,25,...)

a1=7

a2=(7+5)=12

a3=(12+10)=22

a4=(22+15)=37

a5=(37+20)=57

a6=(57+25)=82

35) 1, 4, 9, 16, 25 , 36, 49

#Multiply by with same number to other same number

a1=(1 x 1)=1

a2=(2 x 2)=4

a3=(3 x 3)=9

a4=(4 x 4)=16

a5=(5 x 5)=25

a6=(6 x 6)=36

a7=(7 x 7)=49

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