LAW OF SINES
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[tex] \large \bold{\blue{Problem:}} [/tex] Find m∠A. Round off your answer to the nearest tenth.
[tex] \large \bold{\blue{Solution:}} [/tex] Since the given oblique triangle is SSA, we will gonna use the law of sines.
- [tex] \sf \frac{sin \: A}{a} = \frac{sin \: B}{b} [/tex]
- [tex] \sf \frac{sin \: A}{27} = \frac{sin \: 95°}{43} [/tex]
- [tex] \sf 43(sin \: A)= 26.90[/tex]
- [tex] \sf sin \: A = \frac{26.90}{43} [/tex]
- [tex] \sf \angle A = sin^{-1}(\frac{26.90}{43}) [/tex]
- [tex] \sf \angle A = 38.72° [/tex]
[tex] \large \therefore \boxed{\tt \purple{\angle A = 38.72 \sf °}} [/tex]
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