Question:
What is the theoretical probability that you will roll a number on the die.
A. P(1)
B. P(2)
C. P(3)
D. P(4)
E. P(5)
F. P(6)
Answer:
solve for Probability of desired event P(event) as,
[tex]\sf P(event) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P = Probability of Desired Event}\\\\\text{\sf FO = Favored Outcome = depends on desired event}\\\\\text{\sf TO = Total Outcome = Total number of objects}[/tex]
Solve for Probability of rolling a number 1, P(1)
[tex]\sf P(1) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P = Probability of rolling the number 1}\\\\\text{\sf FO = Favored Outcome = 1 (only one number 1 on a die)}\\\\\text{\sf TO = Total Outcome = 6 (total of 6 numbers on a die)}\\\\\sf P(1) = \frac{FO}{TO} \\\\\sf P(1) = \frac{1}{6}[/tex]
For all other numbers, P(2), P(3), P(4), P(5) and P(6),
They all have the same theoretical probability of 1/6, hence,
P(2) = 1/6
P(3) = 1/6
P(4) = 1/6
P(5) = 1/6
P(6) = 1/6
#No to copy paste solution
#No to plagiarism
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