Question:
a bag has 1 blue 3 green 2 red and 2 yellow marble . find the probability of drawing :
5.blue marble? a.1/8 b.1/4 c.1/7 d.1
6.green marble? a.1/8 b.4/3 c.1/5 d.3
7. yellow marble? a.1/8 b.3/8 c.1/4 d.2
8.white marble? a.1/8 b.3/4 c.1/5 d.0
Answer:
solve for Probability of desired event P(event) as,
[tex]\sf P(event) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P = Probability of Desired Event}\\\\\text{\sf FO = Favored Outcome = depends on desired event}\\\\\text{\sf TO = Total Outcome = Total number of objects}[/tex]
#5. Solve for Probability of drawing a blue marble P(blue),
[tex]\sf P(blue) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P(blue) = Probability of drawing a blue marble}\\\\\text{\sf FO = Favored Outcome = 1 (1 blue marble)}\\\\\text{\sf TO = Total Outcome = 8 (8 total marbles)}\\\\\sf P(blue) = \frac{FO}{TO} \\\\\sf P(blue) = \frac{1}{8}\\\\\\[/tex]
#6. Solve for Probability of drawing a green marble P(green),
[tex]\sf P(green) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P(green) = Probability of drawing a green marble}\\\\\text{\sf FO = Favored Outcome = 3 (3 green marbles)}\\\\\text{\sf TO = Total Outcome = 8 (8 total marbles)}\\\\\sf P(green) = \frac{FO}{TO} \\\\\sf P(green) = \frac{3}{8}\\\\\\[/tex]
#7. Solve for Probability of drawing a yellow marble P(yellow),
[tex]\sf P(yellow) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P(yellow) = Probability of drawing a yellow marble}\\\\\text{\sf FO = Favored Outcome = 2 (2 yellow marbles)}\\\\\text{\sf TO = Total Outcome = 8 (8 total marbles)}\\\\\sf P(yellow) = \frac{FO}{TO} \\\\\sf P(yellow) = \frac{2}{8}\\\\\sf P(yellow) = \frac{1}{2} \\\\\\[/tex]
#8. Solve for Probability of drawing a white marble P(white),
[tex]\sf P(white) = \frac{FO}{TO} \\\\where,\\\\\text{\sf P(white) = Probability of drawing a white marble}\\\\\text{\sf FO = Favored Outcome = 0 (0 white marble)}\\\\\text{\sf TO = Total Outcome = 8 (8 total marbles)}\\\\\sf P(white) = \frac{FO}{TO} \\\\\sf P(white) = \frac{0}{8} \\\\\sf P(white) = 0\\\\\\[/tex]
* as always, double check my answers for errors or carelessness.
#Answers with no solution are as good as copy paste solution!
#NO TO GUESS GUESS, TSAMBA TSAMBA & COPY PASTE SOLUTION!
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