Answer:
(mg)(s)
Explanation:
The problem tells us he falls vertically off the ladder (straight down), so we don't need to worry about motion in the horizontal direction.
The equation for momentum is:
p = mv
We can assume he falls from rest, which allows us to find the initial momentum.
m x 0[tex]\frac{m}{s\\}[/tex] = 0[tex]\frac{kg(m)}{s}[/tex]
From here, we can use the formula for impulse:
Δp = FΔt
(pf − pi) = FΔt
We know his initial momentum is zero, so we can remove this variable from the equation.
pf = FΔt
The problem tells us that his change in time is s seconds, so we can insert this in place of the time.
pf = (F)(s)
The only force acting upon man is the force due to gravity, which will always be given by the equation FG = mg.
pf = (FG)(s)
pf = (mg)(s)
