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An archer stands at rest on frictionless
ice and fires a 0.5-kg arrow
horizontally 50.0 m/s. The
combined mass of the archer and bow
is 60.0 kg. With what velocity does the
archer move across the ice after firing
the arrow?

Sagot :

FierceFireflieego

Answer:-

  • Mass of bow=m1=0.5kg
  • Mass of man before firing gun=60-0.5=59.5kg=m2
  • Initial velocity=u_1=50m/s
  • Recoil velocity=u2=?

According to law if conservation of linear momentum.

[tex]\boxed{\sf m_1u_1=m_2u_2}[/tex]

[tex]\\ \sf\longmapsto (0.5)(50)=59.5u_2[/tex]

[tex]\\ \sf\longmapsto 25=59.5u2[/tex]

[tex]\\ \sf\longmapsto u_2=\dfrac{25}{59.5}[/tex]

[tex]\\ \sf\longmapsto u_2=0.4m/s[/tex]

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