Sagot :
[tex]\tt{\huge{\blue{Explanation:}}}[/tex]
The power rating of a load given its voltage and resistance is
[tex]\boxed{P = \frac{V^{2}}{R}}[/tex]
where:
P = power
V = voltage
R = resistance
[tex]\tt{\huge{\red{Solution:}}}[/tex]
Solving for P
[tex]P = \dfrac{V^{2}}{R}[/tex]
[tex]P = \dfrac{(\text{60 V})^{2}}{\text{9 ohm}}[/tex]
[tex]\boxed{P = \text{400 W}}[/tex]
Therefore, the power rating of the electric heater is 400 W
[tex]\\[/tex]
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