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Dudaysagaralgo
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A 4.2kg papaya is pushed across a table. If the acceleration of the papaya is 3 m/s^2 to the left, what is the net external force exerted on the papaya? ​

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Tokamakgo

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The force acting on an object is given by

[tex]\boxed{F = ma}[/tex]

where:

F = force

m = mass

a = acceleration

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for F

F = ma

F = (4.2 kg)(3 m/s²)

[tex]\boxed{F = \text{12.6 N}}[/tex]

Therefore, the net external force exerted on the papaya is 12.6 N.

[tex]\\[/tex]

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