Answer:
Step-by-step explanation:
[tex] \frac{3x + 2}{4x - 5} + \frac{x - 1}{5 - 4x} \\ \frac{3x + 2}{4x - 5} + \frac{x - 1}{ - (4x - 5)} [/tex]
[tex] \frac{3x + 2}{4x - 5} - \frac{x - 1}{4x - 5} \\ \frac{3x + 2 - (x - 1)}{4x - 5} [/tex]
[tex] \frac{3x + 2 - x + 1}{4x - 5} \\ = \frac{2x + 3}{4x - 5} [/tex]