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The third term of a geometric sequence is 48 and the 6th term 3072. Find the common ratio and the 9th term.

SOLUTION:​


Sagot :

Answer:

Step-by-step explanation:

Tn=ar^(n-1) ,  nth term for GP

t3=48

ar^2=48  ----(1)

ar^5=3072----(2)

(2)/(1)

r=4

a=3

t9=3*(4)^8

t9=196608