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A 25 kg boy is riding a merry –go round with a radius of 5m. What is the centripetal force of the boy if his velocity is 6 m/s2?

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The centripetal force exerted on an object is given by

[tex]\boxed{F_{c} = \frac{mv^{2}}{r}}[/tex]

where:

Fc = centripetal force

m = mass

v = velocity

r = radius

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for Fc

[tex]F_{c} = \dfrac{mv^{2}}{r}[/tex]

[tex]F_{c} = \dfrac{(\text{25 kg})(\text{6 m/s})^{2}}{\text{5 m}}[/tex]

[tex]\boxed{F_{c} = \text{180 N}}[/tex]

Therefore, the centripetal force of the boy is 180 N.

[tex]\\[/tex]

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