👤

A 1,500 kg car accelerates uniformaly from 44km/h to 80.0 km/h in 10.0s. What was the net force exerted on the car

Sagot :

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The force acting on an object is given by

[tex]\boxed{F = ma}[/tex]

where:

F = force

m = mass

a = acceleration

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Listing the given values

vf = 80.0 km/h = 22.2222 m/s

vi = 44.0 km/h = 12.2222 m/s

t = 10.0 s

m = 1500 kg

Solving for a

[tex]a = \dfrac{v_{f} - v_{i}}{t}[/tex]

[tex]a = \dfrac{\text{22.2222 m/s} - \text{12.2222 m/s}}{\text{10.0 s}}[/tex]

a = 1.00 m/s²

Solving for F

F = ma

F = (1,500 kg)(1.00 m/s²)

[tex]\boxed{F = \text{1,500 N}}[/tex]

Therefore, the net force exerted on the car is 1,500 N.

[tex]\\[/tex]

#CarryOnLearning