➤ Answer
[tex]{\boxed{\tt{(x-yz)^{3}={\underline{\green{x^{3}-3x^{2}yz+3xy^{2}z^{2}-y^{3}z^{3}}}}}}}[/tex]
Note that in finding the cube of a binomial, we find the sum of:
- the cube of the first term, like [tex]\tt{x^3}[/tex];
- thrice the product of the second term and the square of the first term, like [tex]\tt{-3x^{2}yz}[/tex];
- thrice the product of the first term and the square of the second term, like [tex]\tt{3xy^{2}z^{2}}[/tex]; and
- the cube of the second term, like [tex]\tt{-y^{3}z^3}[/tex].
[tex]{\huge{\underline{\sf{Hope\:It\:Helps}}}}[/tex]
#LetsLearn #BeBrainly
