Find the difference or sum of the each of the following
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[tex] \frac{7}{3} + 1 \frac{3}{4} \\ = \frac{7}{3} + \frac{7}{4} \\ = \frac{28 + 21}{12} \\ = \frac{49}{12} \\ = 4 \frac{1}{12} [/tex]