Answer
1. x ∈ { 4, - 4 }
2. X = [tex]-2 + \sqrt{6}[/tex]
Step-by-step explanation
Solution for 1
[tex]x^{2} -16=0\\\\(x^{2} -16)+16=16\\\\x^{2} -16+16=16\\[/tex]
N = x ∈ { 4, - 4 }
Solution for 2
[tex]x^{2} -5x+6+9x=8\\\\x^{2} +4x+6=8\\\\x^{2} +4x+6-8=8-8\\\\x^{2} +4x-2=0[/tex]
( a = 1, b = 4 and c = -2 )
[tex]x = \frac{-b + \sqrt{b^{2} - 4ac } }{2a} \\\\x = \frac{-(4) +\sqrt{(4)^{2} -4(1)(-2) } }{2(1)} \\\\x = \frac{-4+\sqrt{24} }{2}[/tex]
X = [tex]-2 + \sqrt{6}[/tex]
I'm not forcing you but if you can, please mark my answer as brain`liest. It took so long to evaluate 2.
#isimpforNoether
