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A golf ball has a mass of approximately 0.0046 kg. How much force must be applied in the tee shot so that the ball will move from rest to 0.825 m/s/s?

Sagot :

Answer:

The force must be applied: 0.038 N

Further explanation

Newton's 2nd law explains that the acceleration produced by the resultant force on an object is proportional and in line with the resultant force and inversely proportional to the mass of the object

∑F = m. a

F = force, N

m = mass = kg

a = acceleration due to gravity, m / s²

A golf ball has a mass of 0.046 kg, then :

m = 0.046 kg

The ball will move from rest to 8.25 m\s in 10 seconds, then :

v = 0

u = 8.25

t = 10 s

\begin{gathered}\rm u=v+at\\\\8.25= 0+a.10\\\\a=0.825~m/s^2\end{gathered}

u=v+at

8.25=0+a.10

a=0.825 m/s

2

The applied force :

\begin{gathered}\rm F=m.a\\\\F=0.046\times 0.825\\\\F=0.038~N\end{gathered}

F=m.a

F=0.046×0.825

F=0.038 N

hope it helps