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A displacement vector lying in the xy plane has a magnitude of 50.0m and is directed at an angle of 120° to the positive x axis. What are the rectangular components of this vector?​

Sagot :

Answer:

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Explanation:

Given the magnitude of the vector of 50 m, and we give an angle measured from the measured from the positive X. Axis. Okay, so to find the components of this vector, we just do the sign on the coastline X. Cos the magnitude multiple recalls sine of the angle. So like in 50 m from magnitude 1 20 degrees. For the angle we get negative 25 m And the white companies magnet and sine of the angle. So plug in the numbers again, you get 43.4 m, so these are direct angular components of this vector.