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Math

Answered

By how much the area of the square of side (4y + 5) cm exceed the area of another square of side (3y - 2) cm? A. B. 7y2 - 52y + 21 7y2 + 52y + 21 C. D. 7y2 + 52y - 21 7y2 - 52y - 21

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Answer:

7y² + 52y + 21 = difference of the area of two squares

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