C. Direction: Using the divisibility rules 2, 5, 10, and 3, 6, 9, list down the factors and encircle all the common factors of the given number.

1. 12
24
2. 60
100
3. 18
54
4. 30
120
5. 75
150

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Montanorhodessa043go Montanorhodessa043go · Answer 1

Answer:

1.12=2 is an even number 12=1+2=3 is 3 can be divided by 3 without a remainder? 3÷3=1 so it's divisible by 6

24=4 is an even number so it's divisible by 2 24=2+4=6 is 6 can be divided by 3 without a remainder? 3÷6=2 yes so it is divisible by 3

2.60=since the last digit of 60 is zero it is divisible by 2,5 and 10

100=since the last digit of 100 is zero it is divisible by 2,5 and 10

3. 18=1+8=9 is 9 can be divided by 9 without a remainder? 9÷9=1 yes so it is divisible by 9

54=4 is an even number so it is divisible by 2 54=5+4=9 is 9 can be divided by 3 without a remainder? 3÷9= 3 yes so it is divisible by 6

4. 30= since the last digit is zero so it is divisible by 2, 5 and 10

120=1+2+0=3 is 3 can be divided by 3 without a remainder? 3÷3=1 yes so it is divisible by 3

5. 75=since the last number of 75 is 5 so it is divisible by 5

150=1+5+0= 6 is 6 can be divided by 3 without a remainder? 3÷6=2 yes so it is divisible by 3

Step-by-step explanation:

3 and 9-if the sum of the digits is can be divided without a remainder it is divisible by 3 or 9

6-if the digits are both divisible by 2 and 3 it is divisible by 6

10-if the last number is 0 it is divisible by 10

5-if the last number is 0 or 5 it is divisible by 5

2-if the last number is 0,2,4,6 and 8 it is divisible by 2