Answer:
Correct answer:
Correct answer:31
Correct answer:31Explanation:
Correct answer:31Explanation:Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.
Correct answer:31Explanation:Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.The sum of the first three terms is (x−d)+x+(x+d)=111.
Correct answer:31Explanation:Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.The sum of the first three terms is (x−d)+x+(x+d)=111.x+x+x+d−d=3x=111
Correct answer:31Explanation:Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.The sum of the first three terms is (x−d)+x+(x+d)=111.x+x+x+d−d=3x=111x=1113=37
Correct answer:31Explanation:Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.The sum of the first three terms is (x−d)+x+(x+d)=111.x+x+x+d−d=3x=111x=1113=37Now we know that the second term is 37. The fourth term is the second term plus twice the common difference: x+2d. Since the second and fourth terms are 37 and 49, respectively, we can solve for the common difference.
Correct answer:31Explanation:Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.The sum of the first three terms is (x−d)+x+(x+d)=111.x+x+x+d−d=3x=111x=1113=37Now we know that the second term is 37. The fourth term is the second term plus twice the common difference: x+2d. Since the second and fourth terms are 37 and 49, respectively, we can solve for the common difference.x+2d=37+2d=49
Correct answer:31Explanation:Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.The sum of the first three terms is (x−d)+x+(x+d)=111.x+x+x+d−d=3x=111x=1113=37Now we know that the second term is 37. The fourth term is the second term plus twice the common difference: x+2d. Since the second and fourth terms are 37 and 49, respectively, we can solve for the common difference.x+2d=37+2d=492d=12
Correct answer:31Explanation:Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.The sum of the first three terms is (x−d)+x+(x+d)=111.x+x+x+d−d=3x=111x=1113=37Now we know that the second term is 37. The fourth term is the second term plus twice the common difference: x+2d. Since the second and fourth terms are 37 and 49, respectively, we can solve for the common difference.x+2d=37+2d=492d=12d=6
Correct answer:31Explanation:Let d be the common difference, and let x be the second term. The first three terms are, in order, x−d,x,x+d.The sum of the first three terms is (x−d)+x+(x+d)=111.x+x+x+d−d=3x=111x=1113=37Now we know that the second term is 37. The fourth term is the second term plus twice the common difference: x+2d. Since the second and fourth terms are 37 and 49, respectively, we can solve for the common difference.x+2d=37+2d=492d=12d=6The common difference is 6. The first term is x−d=37−6=31.
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