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4Ag(s) + O2 (g) + 4H+ (aq) → 4Ag+ (aq) + 2H2O (l)

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Adriennemalolosgo

Answer:

here i hope it helps<3

Explanation:

Part A: O2(g) + 2H2O(l) + 4Ag(s) → 4OH−(aq) + 4Ag+(aq)

Calculate E°cell.

Ag(s) → Ag(aq) + 1 e– E°cell = 0.80 V anode

O2(g) + 2H2O(l) + 4 e– → 4 OH–(aq) E°cell = 0.40 V cathode

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