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1. What is the 9th term of the geometric sequence 192, 48, 12, 3,...? ​

Sagot :

Jamelbenibrahimgo

Answer:

[tex]a_{1} = 192 \\ a_{2} = 48 \\ r = \frac{a_{2}}{a_{1}} = \frac{48}{192} = \frac{1}{4} \\ a_{9} = a_{4} {r}^{9 - 4} = (3) {( \frac{1}{4} )}^{5} = \frac{3}{ {4}^{5} } = \frac{3}{1024} [/tex]

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