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A 30 kg crate is pushed 15 m across the floor. If 19 N of force was used to achieve this motion, how much work was done?

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Tokamakgo

[tex]\tt{\huge{\blue{Explanation:}}}[/tex]

The work done by an object exerting a force F at a distance d is given by

[tex]\boxed{W = Fd}[/tex]

where:

W = work

F = force

d = distance

[tex]\tt{\huge{\red{Solution:}}}[/tex]

Solving for W

W = Fd

W = (19 N)(15 m)

[tex]\boxed{W = \text{285 J}}[/tex]

Therefore, the work done is 285 J.

[tex]\\[/tex]

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