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if one rooy of the quadratic equation 2x²+kx-6=0 is 2, the value of k is?​

Sagot :

Answer:

−1

Step-by-step explanation:

Since x=2 is a root of the equation

2x

2

+kx−6=0

2k+2=0

k=−1

Putting k =-1 in the given equation, we get,

2x

2

−x−6=0

(x−2)(2x+3)=0

x=2,−

2/3