Sagot :
Problem 1:
The ball has kinetic energy.
Solution:
Note: 15 g = 0.015 kg
[tex]KE = \dfrac{1}{2}mv^{2}[/tex]
[tex]KE = \dfrac{1}{2}(\text{0.015 kg})(\text{7 m/s})^{2}[/tex]
[tex]\boxed{KE = \text{0.3675 J}}[/tex]
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Problem 2:
It has potential energy.
Solution:
Note: 20 g = 0.02 kg
PE = mgh
PE = (0.02 kg)(9.8 m/s²)(4)
[tex]\boxed{PE = \text{0.784 J}}[/tex]
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Problem 3:
The ball has kinetic energy.
Solution:
Note: 1,050 g = 1.05 kg
[tex]KE = \dfrac{1}{2}mv^{2}[/tex]
[tex]KE = \dfrac{1}{2}(\text{1.05 kg})(\text{15 m/s})^{2}[/tex]
[tex]\boxed{KE = \text{118.125 J}}[/tex]
[tex]\\[/tex]
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