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1. A 50 kg sack of rice is placed inside a
the truck of 2 m high. what is the potential energy of the sack of rice ?

ans and solution:


2. the hanging bell has a potential energy of 50 joules. if the bell is 5 m above the ground, what will be its mass ?


ans and solution :











pls paki ans ng maayos po ​

Sagot :

Tokamakgo

Problem 1:

Solution:

PE = mgh

PE = (50 kg)(9.8 m/s²)(2 m)

[tex]\boxed{PE = \text{980 J}}[/tex]

Answer:

980 J

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Problem 2:

Solution:

[tex]m = \dfrac{PE}{gh}[/tex]

[tex]m = \dfrac{\text{50 J}}{(\text{9.8 m/}\text{s}^{2})(\text{5 m})}[/tex]

[tex]\boxed{m = \text{1.02 kg}}[/tex]

Answer:

1.02 kg

[tex]\\[/tex]

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