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The number of real solutions of (x2 + 1)2 + 2(x2 + 1) - 3 = 0 is equal to​

Sagot :

Step-by-step explanation:

Let u = x2 + 1 and rewrite the given equation in terms of u as follows

u 2 + 2u - 3 = 0

Factor and solve the above equation

(u + 3)(u - 1) = 0

two solutions: u = x2 + 1 = - 3 and u = x2 + 1 = 1

Equation x2 + 1 = - 3 has no real solutions. Solve the equation x2 + 1 = 1 for to get

x = 0.

The given equation has one real solution.