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vertical asymptote of g(x) =x–3/2x²–8​

Sagot :

Answer:

  • g(x) is defined using the slash, /, as the division sign so g(x) = (3/x^2) - 9. Therefore, g(x) has a vertical asymptote, x = 0 (the y-axis), since the value of x for which the denominator is zero is 0.
  • g(x) is defined using the slash, /, as the division sign so g(x) = (3/x^2) - 9. Therefore, g(x) has a vertical asymptote, x = 0 (the y-axis), since the value of x for which the denominator is zero is 0.But, what if g(x) = 3 / (x^2 - 9). Note, the denominator, x^2 - 9 = 0 when and only when (x + 3)(x - 3) = 0 when and only when x = -3 or x = 3. Therefore, g(x) has two vertical asymptotes, x = -3 and x = 3.