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Renz Joseph saved Php10 on the first day, Php15 on the second day, Php20 on the third day and so on. If the pattern continues, how much will he save for one year?

thanks!!​


Sagot :

Answer:

Step-by-step explanation:

5,10,15,20,25,30 and so on

So this will be an AP

number of days in 1 year=365

A1=5,

d=5

An=A1+(n-1)d

A365=5+(365-1)5=5+364*5=5+1820=1825

SO

he will save for one year=1825