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Jensoo47go
Answered

5. Find a number that is 56 less than its square.​

Sagot :

Jchanda2001go

Answer:

Step-by-step explanation:

Let number is X

so according to given condition

x²-x=56

x²-x-56=0

x²-8x+7x-56=0

x(x-8)+7(x-8)=0

(x-8)(x+7)=0

so

x=8,-7

but only 8 is possible solution

8²-8=64-8=56

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