Sagot :
Answer:
Since both terms are perfect cubes, factor using the difference of cubes formula,
a
3
−
b
3
=
(
a
−
b
)
(
a
2
+
a
b
+
b
2
)
where
a
=
x
and
b
=
1
.
(
x
−
1
)
(
x
2
+
x
⋅
1
+
1
2
)
(
x
−
1
)
(
x
2
+
x
+
1
)
Answer:
Since both terms are perfect cubes, factor using the difference of cubes formula,
a
3
−
b
3
=
(
a
−
b
)
(
a
2
+
a
b
+
b
2
)
where
a
=
x
and
b
=
1
.
(
x
−
1
)
(
x
2
+
x
⋅
1
+
1
2
)
(
x
−
1
)
(
x
2
+
x
+
1
)