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.What is the percent by mass of 25.0g of sodium acetate mixed with 40g of water?
Given:
Formula:
Solution:
NEED HELP


Sagot :

Given:

mass of solute = 25.0 g

mass of solvent = 40.0 g

Required:

percent by mass

Formula:

[tex]\text{percent by mass} = \dfrac{\text{mass of solute}}{\text{mass of solute + mass of solvent}} \times 100[/tex]

Solution:

[tex]\text{percent concentration} = \dfrac{\text{25.0 g}}{\text{25.0 g + 40.0 g}} \times 100[/tex]

Final Answer:

percent by mass = 38.5%

[tex]\\[/tex]

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