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determine the discriminant and nature of roots of each quadtratic equation show your solution on the space provided.
4. 4x² - 12x + 9 = 0​


Sagot :

QUADRATIC EQUATION

Direction: Determine the discriminant of 4x²-12x+9=0 and the nature of roots.

Final Answer:

  • Discriminant: 0
  • Nature of roots: Real and equal

Step-by-step explanation:

4x² - 12x + 9 = 0

First, identify the value of a, b, and c.

Given:

  • a = 4
  • b = -12
  • c = 9

Second, write the formula.

Formula to be used: [tex]\: \bold{ {b}^{2} - 4ac}[/tex]

Lastly, solve using the formula then identify its nature of roots.

[tex]\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} {b}^{2} - 4ac \\ {(-12)}^{2} - 4(4)(9) \\ 144 - 144 \\ 0 \end{gathered} \end{gathered} \end{gathered} \end{gathered} [/tex]

Thus, the discriminant is 0 and the nature of roots is real and equal.