Answer:
1.a2=135
405, 135, 45, 15
an=alrn=1
15=405r⁴=1
15=405r³
15/405 =405r³/405
1/27 =r³
3 1/7 =√43
1/3=r
2.4,28,196,
The common ratio of the geometric sequence is 7
4x7 = 28
28x7 = 196
196x7 = 1,372
1372x7 = 9,604
9604x7 = 67,228
67,228x7 = 470,596
470,596x7 = 3,294,172
3,294,172x7 = 23,059,204
3.just use the formula
(a sub n = a sub 1 • r raise to n-1)
n- means the number of term
a sub 1 - means the first term
a sub n - means the last term
r - means the common ratio
4.2,6,18,54,162,486,
1458,4374,13122, 39366, 118098
5.36,12,4 is in G .P(geometric progression)
first term =a= 36
common ratio =r = 36/12=4/12=1/3
sum of infinite terms = a/(1-r)
= 36/(1-1/3)
= 36/ (2/3)
= 36* 3/2
=18×3
=54
Step-by-step explanation:
hope it helps
pa brainliest
