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1) Calculate the potential energy of a spring compressed from an initial lengths of 15 cm to a final length of 10 cm. The force constant is 7N/m.

2.) A volleyball player served a ball weighing 280 g (convert to kg) to the air with the height of 325 cm. By how much is she changing the gravitational potential energy of the ball?

3.) Find the combined of 4 people that are being lifted by a hot air balloon, with the tension of rope which is 2650 N. What is done by the weight and by the tension on the people after they are moved from rope to rope with a distance of 35 m?​


Sagot :

Answer:

1.I'm assuming that you are asking what is the elastic potential energy stored in the spring at the position stretched by 16.5 cm...

Since you know the spring constant k, 144 N/m and the spring stretch from the equilibrium position x, is 16.5 cm, or 0.165, you find the spring's potential energy from the equation PE = 1/2 kx² which equals 1.96 Joules, or kg *m²/s²if you want SI units.

2

Explanation: